One end of string of length `l` is connected to a particle on mass `m` and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed `v` the net force on the particle (directed toward centre) will be (`T` reprents the tension in the string):

Options

A. T
B. `T+(mv^(2))/(l)`
C. `T-(mv^(2))/(l)`
D. Zero

Answer

A

Explanation

Centripetal force `((mv^(2))/(l))` is provided by tension so the net force will be equal to tension i.e. , T.