The ratio of wavelength of the lest line of Balmer series and the last line Lyman series is:

Options

A. 2
B. 1
C. 4
D. 0.5

Answer

C

Explanation

For last Balmer series
`(1)/(lambda_(b))=R[(1)/(2^(2))-(1)/(oo^(2))]`
`lambda_(b)=(4)/(R)`
For last Lyman series
`(1)/(lambda_(l))=R[(1)/(1^(2))-(1)/(oo^(2))]`
`lambda_(l)=(1)/(R)`
`(lambda_(b))/(lambda_(l))=((4)/(R))/((1)/(R))`
`(lambda_(b))/(lambda_(l))=4 `