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The two nearest harmonics of a tube clos...

The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?

A

10 Hz

B

20 Hz

C

30Hz

D

40 Hz

Text Solution

Verified by Experts

The correct Answer is:
B
Two successive frequencies of closed pipe
`(nv)/(rl)=220` .....(i)
`((n+2)v)/(4I)=260` ...... (ii)
Dividing (ii) by (i) , we get
`(n+2)/(n)=(260)/(220)=(13)/(11)`
` 11n+22=13n`
` n=11 `
So, ` 11 (v)/(4I)=220`
`(v)/(4l)=20`
So fundamental frequency is 20 Hz .
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