The efficiency of an ideal heat engine working between the freezing point and boiling point of water, is

Options

A. `6.25%`
B. `20%`
C. `26.8%`
D. `12.5%`

Answer

C

Explanation

Efficiency of ideal heat engine, `eta=(1-(T_(2))/(T_(1)))`
`T_(2)` : Sink temperature
`T_(1)`: Source temperature
`% eta=(1-(T_(2))/(T_(1)))xx100`
`=(1-(273)/(373))xx100`
`=((100)/(373))xx100=26.8%`