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A set of 'n' equal resistor, of value of...

A set of `'n'` equal resistor, of value of `'R'` each are connected in series to a battery of emf `'E'` and internal resistance `'R'`. The current drawn is `I`. Now, the `'n'` resistors are connected in parallel to the same battery. Then the current drawn from battery becomes 10.1. The value of `'n'` is

A

20

B

11

C

10

D

9

Text Solution

Verified by Experts

The correct Answer is:
C
`I=(E)/(nR+R)" "…(i)`
`10I=(E)/((R)/(n)+R)" "…(ii)`
Dividing (ii) by (i)
`10=((n+1)R)/(((1)/(n)+1)R)`
After solving the equation , n=10
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