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In young's double slit experiment the se...

In young's double slit experiment the separation `d` between the slits is `2mm`, the wavelength `lambda` of the light used is `5896 Å` and distance `D` between the screen and slits is `100 cm`. It is found that the angular width of the fringes is `0.20^(@)`. To increases the fringe angular width to `0.21^(@)`(with same `lambda` and `D`) the separtion between the slits needs to be changed to

A

2.1 mm

B

1.9 mm

C

1.8 mm

D

1.7 mm

Text Solution

Verified by Experts

The correct Answer is:
B
Angular width `=(lambda)/(d)`
`0.20^(@)=(lambda)/(2 mm)" "…(i)`
`0.21^(@) = (lambda)/(d)" "…(ii)`
Dividing we get , `(0.20)/(0.21)=(d)/(2 mm)`
`therefore` d=1.9 mm
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