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A metallic rod of mass per unit length 0...

A metallic rod of mass per unit length `0.5 kg m^(-1)` is lying horizontally on a straght inclined plane which makes an angle of `30^(@)` with the horizontal. The rod is not allowed to slide down by flowing a current throguh it when a magnetic field of induction `0.25 T` is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is

A

14.76 A

B

5.98 A

C

7.14 A

D

11.32 A

Text Solution

Verified by Experts

The correct Answer is:
D
For equilibrium
mg sin `30^(@)` =l/B cos `30^(@)`
`I=(mg)/(lB)tan 30^(@)`
`=(0.5xx9.8)/(0.25xxsqrt(3))=11.32 A `
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