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Current senstivity of moving coil galvan...

Current senstivity of moving coil galvanometer is `5 "div"//mA` and its voltage senstivity (angular deflection per unit voltage applied) is `20 "div"//V`. The resistance of the galvanometer is

A

`250 Omega`

B

`25 Omega`

C

`40 Omega`

D

`500 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
Current sensitivity
`I_(s)=(NBA)/(C)`
`Voltage sensitivity
`V_(s)=(NBA)/(CR_(G))`
So, resistance of galvanometer
`R_(G)=(I_(s))/(V_(s))=(5xx1)/(20xx10^(-3))=(5000)/(20)=250 Omega`
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