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A sample of 0.1 g of water of 100^(@)C a...

A sample of `0.1 g` of water of `100^(@)C` and normal pressure `(1.013 xx 10^(5) N m^(-2))` requires 54 cal of heat energy to convert to steam at `100^(@)C`. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample is

A

42.2 J

B

208.7 J

C

104.3 J

D

84.5 J

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaQ=DeltaU+DeltaW`
`implies 54xx4.18=DeltaU+1.013xx10^(5)(167.1 xx 10^(-6)-0)`
`implies DeltaU=208.7 J`
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