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A mixture of 2.3 g formic acid and 4.5 g...

A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. `H_(2)SO_(4)`. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be

A

2.8

B

3

C

1.4

D

4.4

Text Solution

Verified by Experts

The correct Answer is:
A

`underset(2.3 g " or "((1)/(20)"mol"))(HCOOH)overset("Conc". H_(2)SO_(4))to underset((1)/(20)"mol")(CO(g))+H_(2)O(l)`
`underset(4.5 g " or "((1)/(20) "mol"))underset(COOH" ")underset(|" ")(COOH)overset("Conc." H_(2)SO_(4))to underset((1)/(20)"mol")(CO(g))+underset((1)/(20)"mol")(CO_(2)(g))+H_(2)O(l)`
Gaseous mixture formed is CO and `CO_(2)` when it is passed through KOH, only `CO_(2)` is absorbed . So the remaining gas is CO.
So, weight of remaining gaseous product CO is
`(2)/(20)xx28=2.8 g`
So, the correct option is(1)
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