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The solubility of BaSO(4) in water is 2....

The solubility of `BaSO_(4)` in water is `2.42xx10^(-3) gL^(-1)` at `298 K`. The value of its solubility product `(K_(sp))` will be (Given molar mass of `BaSO_(4)=233 g mol^(-1)`)

A

`1.08xx10^(-14) "mol"^(2)L^(-2)`

B

`1.08xx10^(-12) "mol"^(2)L^(-2)`

C

`1.08 xx 10^(-10) "mol"^(2)L^(-2)`

D

`1.08 xx 10^(-8) "mol"^(2) L^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Solubility of `BaSO_(4), s=(2.42xx10^(-3))/(233) ("mol" L^(-1))`
`=1.04xx10^(-5) ("mol" L^(-1))`
`BaSO_(4)(s) hArr underset(s)(Ba^(2))(aq) + underset(s)(SO_(4)^(2-))(aq)`
`K_(sp)=[Ba^(2+)][SO_(4)^(2-)]=s^(2)`
`=(1.04xx 10^(-5))^(2)`
`=1.08xx10^(-10) "mol"^(2)L^(-2)`
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