For the redox reaction
`MnO_(4)^(ө)+C_(2)O_(4)^(2-)+H^(o+)rarrMn^(2+)+CO_(2)+H_(2)O`
the correct coefficients of the reactions for the balanced reaction are

Options

A. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-) ,H^(+)),(2,16,5):}`
B. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-) ,H^(+)),(2,5,16):}`
C. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-) ,H^(+)),(16,5,2):}`
D. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-) ,H^(+)),(5,16,2):}`

Answer

B

Explanation

n-factor of `MnO_(4)^(-) implies 5`
n-factor of `C_(2)O_(4)^(2-)implies 2`
Ratio of n-factor of `MnO_(4)^(-)` and `C_(2)O_(4)^(2-)` is 5:2 So, molar in balanced reaction is 2:5
`therefore ` The balanced equation is
`2MnO_(4)^(-) + 5C_(2)O_(4)^(2-) +16H^(+) to 2Mn^(2+) + 10CO_(2) + 8H_(2)O`