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Two pendulums suspended from same point ...

Two pendulums suspended from same point having length 2m and 0.5m. If they displaced slightly and released then they will be in same phase, when small pendulum will have completed :

A

2 oscillation

B

4 oscillation

C

3 oscillation

D

5 oscillation

Text Solution

Verified by Experts

The correct Answer is:
A

`(N+1)T_(s)=NT_(l)`because`Tpropsqrt(l)`
`implies (N+1)/N=sqrt((l_(l))/(l_(s)))=sqrt((2)/(0.5))=2`
`implies (N+1)/N=2impliesN=1impliesN+1=2`
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