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Work function of a metal surface is phi=...

Work function of a metal surface is `phi=1.5eV`. If a light of wavelength 5000Å falls on it then the maximum K.E. of ejected electron will be-

A

1.2 eV

B

0.98 eV

C

0.45 eV

D

0 eV

Text Solution

Verified by Experts

The correct Answer is:
B
`K.E_(max)=(hc)/lamda-phi`
=(12400eVÅ)/(5000Å)-1.5eV
=(2.48-1.5)eV=0.98 eV
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