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for nuclear reaction : .(92)U^(235)+.(...

for nuclear reaction :
`._(92)U^(235)+._(0)n^(1)to._(56)Ba^(144)+.......+3_(0n^1)`

A

`._(26)Kr^(89)`

B

`._(36)Kr^(89)`

C

`._(26)Sr^(90)`

D

`._(38)Sr^(89)`

Text Solution

Verified by Experts

The correct Answer is:
B
`._(92)U^(235) + ._(0)n^(1) to ._(56)Ba^(144) + ._(Z)X^(A) + 3._(0)n^(1)`
235 + 1 = 144 + A +3 `implies` A = 89
92 + 0 = 56 + Z + 0 `implies` Z = 36
Therefore `._(36)X^(89) to ._(36)Kr^(89)`
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