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A particle is projected with velocity 'u...

A particle is projected with velocity 'u' makes an angle `theta` w.r.t. horizontal. Now it breaks in two identical parts at highest point of trajectory. If one part is retrace its path, then velocity of other part is -

A

3u cos `theta`

B

2u cos `theta`

C

u cos `theta`

D

u

Text Solution

Verified by Experts

The correct Answer is:
A

`"mu"costheta=-"mu"/2costheta+m/2v'`
`v'=3ucostheta`
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