Two springs A and B (KA = 2 KB) are stre...

Two springs A and B `(K_A = 2 K_B)` are stretched by same suspended weights then ratio of workdone in stretching is -

`1:2`

`2:1`

`1:1`

`1:4`

Text Solution

Verified by Experts

The correct Answer is:

`W=1/2Kx^2, F=-Kx`
`W=1/2K.F^2/K^2=F^2/(2K)`
`Wprop1/KimpliesW_A/W_B=K_B/K_A=K_B/(2K_B)=1/2`

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