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Light of wavelength 300 Å in Photoelectr...

Light of wavelength 300 Å in Photoelectric effect gives electron of max. K.E. 0.5 eV. If wavelength change to 2000 Å then max. K.E. of emitted electrons will be

A

Less than 0.5 eV

B

0.5 eV

C

Greater than 0.5 eV

D

PEE does not occurs

Text Solution

Verified by Experts

The correct Answer is:
A
`K.E_(max)=(hc)/(lamda)-phi`
Then K.E. will be greater than 0.5 eV
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