If `A, B, C` are in `A.P.`, then correct relation is `cotA=(sinB+sinC)/(cosC+sinB)`

In a DeltaABC , cosecA (sinB cosC + cosB sinC) =

if A, B, C are acute positive angles, then : ((sinA + sinB)(sinA + sinC)(sinA + sinC))/(sinA sinB sinC) is :

If A,B and C are the angle of a triangle show that |{:(sin2A,sinC,sinB),(sinC,sin2B,sinA),(sinB,sinA,sin2C):}|=0.

If A,B and C are the angle of a triangle show that |{:(sin2A,sinC,sinB),(sinC,sin2B,sinA),(sinB,sinA,sin2C):}|=0.

For DeltaABC , sinA + sinB + sinC

In a DeltaABC, sin A sinB sinC is

In a DeltaABC, sin A sinB sinC is

If in aDeltaABC,sinA,sinb,sinC are in A.P ., then

If A,B,C, are the angles of a triangle such that cotA/2=3tanC/2, then sinA ,sinB ,sinC are in AdotPdot (b) GdotPdot (c) HdotPdot (d) none of these