The equilibrium constant for a reaction is `2 xx 10^(-23) " at " 25^(@)C " and " 2xx 10^(-2) " at " 50^(@)C.` Is the reaction endothermic or exothermic ?

The equilibrium constant of a reaction is 2xx10^(-3) at 25^@C and 2xx10^(-2) at 50^@C . Is the reaction exothermic on endothermic? Explain.

The rate constant of a reactant is 1.5 xx 10^(-3) at 25^(@)C and 2.1 xx 10^(-2) at 60^(@)C . The activation energy is

The rate constant of a reactant is 1.5 xx 10^(-3) at 25^(@)C and 2.1 xx 10^(-2) at 60^(@)C . The activation energy is

The equilibrium constants of a reaction at 27^@ C and 127^@ C are 1.6 xx 10^(-3) and 7.6 xx 10^(-2) respectively. Is the reaction exothermic or endothermic ?

The equilibrium constants of a reaction at 27^(@)C and aet 127^(@)C are 1.6xx10^(-3) and 7.6xx10^(-2) respectively. Is the reaction exothermic or endothermic?

The values of equilibrium constant (K) of a reaction at 25^(@)C and 50^(@)C are 2xx10^(-4) and 2xx10^(-2) respectively. Is the reaction an exothermic or an endothermic reaction?