Calculate the distance between (111) planes in a crystal of calcium. Repeat the calculation for (222) planes. Which palnes are closer ? (a = 0.556 nm)

Explanation

To calculate the distance between the (111) and (222) planes in a crystal of calcium, we will use the formula for the distance between planes in a crystal lattice:

\[ d_{hkl} = \frac{a}{\sqrt{h^2 + k^2 + l^2}} \]

where:
- \(d_{hkl}\) is the distance between the planes,
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