Using X -rays of wavelength 154.1 pm and staring from the glancing angle, the reflection fro sliver crystal was found to occur at ` theta = 22.20^(@)`. Calculate the spacing between the planes of Ag atoms that gave rise to the above reflection. `(sin 22.20^(@) = 0.3778)`

Explanation

Here ,` lambda = 154.1 "pm" n =1 , theta = 22.20^(@)`
Using Bragg's equation ,viz , ` 2 d sin theta =n lambda`
` d = ( n lambda)/(2 sin theta) = ( 1 xx 154.1)/( 2xx0.3778) "pm" = 204"pm"`