Calculate the number of unit cells in 8.1 g of aluminium if it crystallizes in a face-centred cubic (f.c.c.) structure. (atomic mass of Al=27g `mol^(-1)`)

Explanation

1 mole of Al=27 g `=6.02xx10^23` atoms
`therefore` No. of Al atoms present in 8.1 g of Al`=(6.02xx10^23)/27xx8.1=1.806xx10^23`
As face-centered cubic cell contains 4 atoms , therefore, number of unit cells present =`(1.806xx10^23)/4=4.515xx10^22`