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CsCl has bc c arrangement and its unit c...

`CsCl` has `bc c` arrangement and its unit cell edge length is `400` pm. Calculate the interionic distance in `CsCl`.

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where black circle is `Cs^+` ion and coloured circles are `Cl^-` ions. The aim is to find half of the body diagonal AE. If the edge of the unit cell is 'a', then
`CE=sqrt(a^2+a^2)=sqrt2a`
`therefore AE=sqrt((sqrt2a)^2+a^2)=sqrt3a=sqrt3xx400`
`therefore` Interionic distance `=1/2AE=sqrt3xx200=346.4` pm
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