In solid, oxide ions are arranged in ccp. One sixth of the tetrahedral voids are occupied by the cations (A) while one third of the octahedral voids, are occupied by the cations (B). What is the formula of the compound ?

Answer

`ABO_3`

Explanation

Suppose `O^(2-)` ions=n. Then octahedral voids=n and tetrahedral voids= 2n. Cations A=`1/6xx2n=n/3` cation B=`1/3xxn=n/3`
`therefore` A:B:`O^(2-)=n/3:n/3:n=1:1:3` , i.e., formula is `ABO_3`