Silver metal crystallises with a face centred cubic lattice. The length of the unit cell is found to be `3.0xx10^(-8)`cm. Calculate atomic radius and density of silver.
Molar mass of Ag`=108 g mol^(-1), N_(A)=6.02xx10^(23)mol^(-1)`).

Answer

`1.06xx10^(-8) "cm", 26.6 "g cm"^(-3)`

Explanation

`a=3.0xx10^(-8)` cm. For fcc, `r=a/(2sqrt2)=(3.0xx10^(-8))/(2xx1.414)=1.06xx10^(-8)` cm
`rho=(ZxxM)/(a^3xxN_A)=(4xx108)/((3.0xx10^(-8))^3xx(6.02xx10^23))=26.6 "g cm"^(-3)`