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Niobium crystallises in body-centred cub...

Niobium crystallises in body-centred cubic structure. If the atomic radius is 143.1 pm, calculate the density of Niobium. (Atomic mass = 93u).

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The correct Answer is:
`8.6 "g cm"^(-3)`
For bcc, `r=sqrt3/4a` or `a="4r"/3=(4xx143.1)/(1.732)`pm =330.5 pm
`rho=(ZxxM)/(a^3xxN_0)=(2xx93)/((330.5xx10^(-10))^3xx(6.02xx10^23))=8.6 "g cm"^(-3)`
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