An element has atomic mass `93 g mol^(-1)` and density `11.5 g cm^(-3)`. If the edge length of its unit cell is 300 pm, identify the type of unit cell.

Answer

BCC

Explanation

`rho=(ZxxM)/(a^3xxN_0), Z=(rhoxxa^3xxN_0)/M =((11.5 g cm^(-3))(300xx10^(-10)cm)^3(6.023xx10^23 mol^(-1)))/(93 g mol^(-1))=2.01 approx2`
Hence, the type of unit cell is BCC.