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Silver crystallises in fcc latice. If ed...

Silver crystallises in fcc latice. If edge length of the unit cell is `4.077xx10^(-8)cm`, then calculate the radius of silver atom.

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`M=(rhoxxa^3xxN_0)/Z=(10.5 "g cm"^(-3) xx (4.077xx10^(-8) cm)^3 xx(6.02xx10^23 "mol"^(-1)))/4=107.09 "g mol"^(-1)`
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