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Aluminium crystallises in a cubic close packed structure. Its metallic radius is 125 pm.
(i) What is the length of the side of the unit cell ?
(ii) How many unit cells are there in ` 1.00 "cm"^(3)` of aluminium ?

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(i)ccp=fcc. For fcc, `a=2sqrt2r`= 2 x 4.414 x 125 pm =354pm
(ii)Volume of one unit cell =`(354xx10^(-10)cm)^3=4.44xx10^(-23) cm^3`
Unit cells in `1 cm^3 =1/(4.44xx10^(-23))=2.25xx10^22`
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