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In diamond lattice, all lattice points a...

In diamond lattice, all lattice points and alternate tetrahedral voids are occupied by carbon atoms. If diamond crystallizes in fcc form with edge length 'a' , find out (a)number of next nearest neighbours in diamond lattice (b)distance between the next nearest neighbours.

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To solve the problem regarding the diamond lattice, we need to follow these steps: ### Step 1: Understanding the Diamond Lattice Structure The diamond lattice is a face-centered cubic (FCC) structure where each carbon atom occupies both the lattice points and alternate tetrahedral voids. In an FCC structure, there are 4 atoms per unit cell. ### Step 2: Finding the Number of Next Nearest Neighbors In the diamond lattice, the next nearest neighbors are located at the tetrahedral voids. Each carbon atom at a lattice point has 4 next nearest neighbors, which are the carbon atoms occupying the tetrahedral voids. ...
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