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Using X -rays of wavelength 154.1 pm an...

Using X -rays of wavelength 154.1 pm and staring from the glancing angle, the reflection fro sliver crystal was found to occur at ` theta = 22.20^(@)`. Calculate the spacing between the planes of Ag atoms that gave rise to the above reflection. `(sin 22.20^(@) = 0.3778)`

Text Solution

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Here, `lambda`=154.1 pm , n=1, `theta=22.20 ^@`
using Bragg's equation , viz. , `2 d sin theta= nlambda`
`d=(nlambda)(2 sin theta)=(1xx154.1)/(2xx0.3778)` pm =204 pm
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