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The number of atoms is 100 g of a fcc cr...

The number of atoms is 100 g of a fcc crystal with density = 10.0 ` g//cm^(3)` and cell edge equal to 200 pm is equal to

A

`5xx10^24`

B

`5xx10^25`

C

`6xx10^23`

D

`2xx10^25`

Text Solution

Verified by Experts

The correct Answer is:
A
`rho=(ZxxM)/(a^3xx10^(-30)xxN_0)` or `M=(10xx(200)^3xx10^(-30)xx6xx10^23)/4=12`
Thus, 12 g contain=`N_0=6xx10^23` atoms
`therefore` 100 g will contain `=(6xx10^23)/12xx100=5xx10^24`
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