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Iron exhibits bcc structure at roomj tem...

Iron exhibits `bcc` structure at roomj temperature. Above `9000^(@)C`, it transformers to `fcc` structure. The ratio of density of iron at room temperature to that at `900^(@)C` (assuming molar mass and atomic radius of iron remains constant with temperature) is

A

`sqrt3/sqrt2`

B

`(4sqrt3)/(3sqrt2)`

C

`(3sqrt3)/(4sqrt2)`

D

`1/2`

Text Solution

Verified by Experts

The correct Answer is:
D
Density `(rho)=(ZxxM)/(a^3xxN_0)`
As M and a remain contant and `N_0` is also constant , `rho prop Z`
`rho_"bcc"/rho_"fcc"=Z_"bcc"/Z_"fcc"=2/4=1/2`
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