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Iron (II) oxide has a cubic strcuture an...

Iron (II) oxide has a cubic strcuture and each unit cell has side 5 Å. If the density of the oxide is 4 g `cm^(-3)`, the number of oxide ions present in each unit cell is ( Molar mass of FeO = ` 72 "g mol"^(-1), N_(A) = 6.02 xx 10^(23) "mol"^(-1)`

Text Solution

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The correct Answer is:
4
`Z=(rhoxxa^3xxN_0)/M`
`=((4 g cm^(-3))(5xx10^(-8)cm)^3(6.02xx10^23 mol^(-1)))/(72 g mol^(-1))approx 4`
Thus, there are 4 formula units (FeO) per unit cell.Hence, `O^(2-)` ions =4
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