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A crystalline solid of a pure substance ...

A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is `8 g cm^(-3)`, then the number of atoms present in 256g of the crystal is `N xx 10^(24)`. The value of `N` is

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The correct Answer is:
2
`rho=(ZxxM)/(a^3xxN_0xx10^(-30))` where a is in pm and M in g `mol^(-1)`
`8=(4xxM)/((400)^3xx6xx10^23xx10^(-30))` or M=76.8
Moles in 256 g =`256/76.8`=3.33
`therefore` No. of atoms =`3.33xx6xx10^23=2xx10^24`
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