Calculate the amount of heat evolved when
(i) `500 cm^(3)` of 0.1 M hydrochloric acid is mixed with `200 cm^(3)` of 0.2 M sodium hydroxide solution
(ii) `200 cm^(3)` of0.2 M sulphuric acid is mixed with `400 cm^(3)` of 0.5 M potassium hydroxide solution.
Assuming that the specific heat of water is `4.18 J K^(-1) g^(-1)` and ignoring the heat absorbed by the container, thermometer, stirrer etc, what would be the rise in temperature in each of the above cases ?

Explanation

To solve the problem, we will break it down into two parts as per the question.

### Part (i): Mixing HCl and NaOH

1. **Calculate moles of HCl:**
- Volume of HCl = 500 cm³ = 0.500 L
- Molarity of HCl = 0.1 M
- Moles of HCl = Molarity × Volume = 0.1 mol/L × 0.500 L = 0.05 moles
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