The enthalpies of solution of anhydrous `CuSO_(4)` and hydrated `CuSO_(4). 5H_(2)O` are -66.5 and 11.7 kJ `mol^(-1)` respectively.Calculate the enthalpy of hydration of `CuSO_(4)` to `CuSO_(4).5H_(2)O`.

Answer

`-78.2kJ mol^(-1)`

Explanation

Given `: (i) CuSO_(4) (s) + aq rarr CuSO_(4) (aq),Delta H =- 66.5 kJ mol^(-1)`
(ii) `CuSO_(4).5 H_(2) O (s) + aq rarr CuSO_(4)(aq), DeltaH = + 11.7 kJ mol^(-1)`
Aim `: CuSO_(4)(s) + 5H_(2)O(l) rarr CuSO_(4).5H_(2)O (s), Delta H = ?`
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