The enthapy of formation of carbon monoxide and steam are -110.5 and -243.0 kJ respectively.Calculate the heat of the reaction when steam is passed over coke as : `C(s) + H_(2)O(g) to CO(g) + H_(2)(g)` .

Answer

`+ 132.5 kJ mol^(-1)`

Explanation

`Delta_(r) H^(@) = [ Delta_(f) H^(@) ( CO) + Delta_(f) H^(@) ( H_(2))]-[Delta_(f) H^(@) (H_(2)O)]`
`=[ - 110.5 + 0 ] - [ 0 + (-243.0)]`
`= + 132.5 kJ mol^(-1)`