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The enthalpy of formation of Fe(2)O(3)(s...

The enthalpy of formation of `Fe_(2)O_(3)(s)` is `-824.2 kJ "mol"^(-1)`.Calculate the enthalpy change for the reaction :
`4Fe(s) + 3O_(2)(g) to 2Fe_(2)O_(3)(s)`

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Verified by Experts

The correct Answer is:
`-1648.4kJ`
`Delta_(r)H^(@) = [ 2 xx Delta_(f) H^(@) ( Fe_(2)O_(3))] - [ Delta_(f)H^(@) ( Fe)+ 3Delta_(f) H^(@) (O_(2))]`
`= [2(-824.2) ] -[0+0]`
`= - 1648.4kJ`
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