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Red phosphorus reacts with liquid bromin...

Red phosphorus reacts with liquid bromine in an exothermic reaction
`2P(s) + 3 Br_(2) (l) rarr PBr_(3) (g), Delta_(r) H^(@) = - 243 kJ`
Calculated the enthalpy change when `2.63 g` of phosphorus reacts with an excess of bromine in this way.

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Verified by Experts

The correct Answer is:
`10.3kJ`
Required `Delta H = ( 243 ) /( 62)xx 2.63 J = 10.3 kJ`
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Red phosphorus reacts with liquid bromine in an exothermic reaction 2P(s) + 3 Br_(2) (l) rarr PBr_(3) (g), Delta_(r) H^(@) = - 243 kJ mol^(-1) Calculated the enthalpy change when 2.63 g of phosphorus reacts with an excess of bromine in this way.

Red phosphorus reacts with liquid bromine in an exotermic reaction : 2P_((s))+3Br_(2(l))rarr2PBr_(3(g)) Delta_(r)H^(@)=-243kJ . Calculate the enthalpy change when 2.63g of phosphorus with an excess of bromine in this way.

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