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Calculate the enthalpy change when 2.38 ...

Calculate the enthalpy change when `2.38 g` of carbon monoxide `(CO)` vaporise at its normal boiling point.

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The correct Answer is:
`513.4J`
`Delta_(vap) H ` for `CO = 6.04 kJ mol^(-1)`, i.e., = 6.04 kJ for28 g
`:. `Enthalpy change for vaporisation of2.38 g `= ( 6.04) /( 28) xx2.38 kJ = 0.5134 kJ= 513.4 J`
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