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The enthalpy of vaporisation of benzene ...

The enthalpy of vaporisation of benzene `(C_(6)H_(6))` is `30.8 kJ mol^(-1)` at its boiling point `(80.1^(@)C)`. Calculate the entropy change in going from:
a. liquid to vapour and
b. vapour to liquid at `80.1^(@)C`.

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The correct Answer is:
`Delta_(vap) S= 87.3 JK^(-1) mol^(-1), Delta_(cond) S = - 87.3 JK^(-1) mol^(-1)`
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PRADEEP-THERMODYNAMICS-PROBLEM FOR PRACTICE
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