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At what temperature does the reduction o...

At what temperature does the reduction of lead oxide to lead by carbon becomes spontaneous?
`PbO +C rarr Pb(s) +CO(g)`
For the reacion, `DeltaH` and `DeltaS` at `25^(@)C` are `108.4 kJ mol^(-1)` and `190 J K^(-1) mol^(-1)` respectively.

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Verified by Experts

The correct Answer is:
Above `570.5K`
At equilibrium, `T = (DeltaH)/(DeltaS) = (108400 J mol^(-1))/( 190 JK^(-1) mol^(_1)) = 570 . 5K`
Above 570.5 K, `Delta G` will be `-ve` and the reaction will be spontaneous.
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