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Calculate the standard entropy change fo...

Calculate the standard entropy change for a reaction `X harr Y`, If the value of `DeltaH^(@) = 28.40 kJ` and equilibrium constant is `1.8 xx 10^(-7)` at 298 K.

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The correct Answer is:
`-33.8 JK^(-1) mol^(-1)`
`Delta_(r)G^(@) = - 2.303 RT log K = + 38484J`
`Delta_(r) G^(@) = Delta_(r)H^(@) - T DeltaS ^(@) , i.e., Delta_(r) S^(@) = ( Delta_(r)H^(@) - Delta_(r)G^(@))/(T)= ( 28400-38484)/(298) = -33.8 J K^(-1) mol^(-1)`
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