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Find out the value of equilibrium consta...

Find out the value of equilibrium constant for the following reaction at 298 K.
`2NH_(3)(g)+CO_(2)(g)hArrNH_(2)CONH_(2)(aq)+H_(2)O(1)`
Standard Gibbs energy change, `Delta_(r)G^(Ө)` at the given temperature is `-13.6 kJ "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
`2.4 xx 10^(2)`
`Delta_(r)G^(@) = - 2.303 RT log K, i.e., - 13600 = - 2.303 xx 8.314 xx 298 log K`
or log K `= 2.38 :. K = ` antilog ` 2.38 xx 2.4 xx 10^(2)`
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