In an ovan , due to insufficient supply of oxygen, `60%` of the carbon is converted to carbon dioxide wehreas the remaining `40%` is converted into carbon monoxide. If the heat of combustion of carbon to `CO_(2)`is `394kJ mol^(-1)` while that of its oxidation to CO is 111 kJ `mol^(-1)`, calculate the total heat produced in the oven by burning 10 kg of coal containing `80%` carbon by weight .Also calculate the efficiency of the oven.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the weight of carbon in the coal
Given that the coal weighs 10 kg and contains 80% carbon by weight, we can calculate the weight of carbon as follows:

\[ \text{Weight of Carbon} = \frac{80}{100} \times 10 \, \text{kg} = 8 \, \text{kg} \]
...