The enthalpy of combustionof 1 mole of `H_(2)` to form `H_(2)O(l)` is`"…........."` kJ whereas to form `H_(2)O(g), ` it is `"…....................."` kJ.

Explanation

To solve the problem regarding the enthalpy of combustion of hydrogen gas (H₂) to form water in both liquid and gaseous states, we can follow these steps:

### Step 1: Understand the Reaction
The combustion of hydrogen can be represented by the following reactions:
1. Formation of liquid water:
\[ 2H_2(g) + O_2(g) \rightarrow 2H_2O(l) \]
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