Home
Class 11
CHEMISTRY
Given that : O(g) + e^(-) to O^(-)(g) D...

Given that :
`O(g) + e^(-) to O^(-)(g) DeltaH = -142 kJ "mol"^(-1)`
`O(g) + 2e^(-) to O^(2-)(g) Delta H = + 712 kJ "mol"^(-1)`
what will be the `DeltaH` for the reaction:
`O^(-)(g) + e^(-) to O^(2-)(g)`

Text Solution

Verified by Experts

Eqn. (ii) - Eqn. (i) gives `O^(-)(g) + e^(-) rarr O^(2-) (g), Delta H =712 -( - 142) kJ mol^(-1) = 854 kJ mol^(-1)`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    PRADEEP|Exercise NCERT QUESTIONS AND EXERCISES WITH ANSWERS|22 Videos

  • THERMODYNAMICS

    PRADEEP|Exercise NCERT SUPPLEMENTARY EXERCISE|6 Videos

  • THERMODYNAMICS

    PRADEEP|Exercise CONCEPTUAL QUESTIONS( II. First law of thermodynamics)|1 Videos

  • STRUCTURE OF ATOM

    PRADEEP|Exercise Competition Focus (JEE (Main and Advanced)/Medical Entrance (IX. Assertion And Reason Type Questions (Type II))|12 Videos

Similar Questions

Explore conceptually related problems

Given that O(g)+e^(-)rarrO^(-)(g) , DeltaH=34Kcal mol^(-1) O(g)+2e^(-)(g)rarrO^(2-)(g) , DeltaH=168Kcal mol^(-1) The enthalply change for the reaction O^(-)(g)+e^(-)rarrO^(2-)(g) is

O(g) + 2e^(-) to O^(2-)(g) , DeltaH_(eg) = 744.7 kJ/mole . The positive value of DeltaH_(eg) is due to :

The formation of oxide ion O^(2-)(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below O(g)+e^(-) rarr O^(-)(g), DeltaH^(-) = - 141 kj mol^(-1) O^(-)(g) +e^(-) rarr O^(2-) (g), DeltaH^(-) =+ 780 kj mol^(-1) Thus, process of formation of O^(2-) in gas phase is unfavourable even through O^(2-) is isoelectronic with neon. It is due to the fact that