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In a process, 701 J of heat is absorbed ...

In a process, `701 J` of heat is absorbed by a system and `394 J` of work is done by the system. What is the change in internal energy for the process?

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`q=+ 701 J ,w = - 394 J , DeltaU =?`
By first law of thermodynamics `Delta U =q +w = + 701 J + ( -394J) = + 307 J`
i.e., internal energy of the system increases by 307J
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